2x^2/3x=36

Solution for 2x^2/3x=36 equation:

2x^2/3x=36

We move all terms to the left:

2x^2/3x-(36)=0


Domain of the equation: 3x!=0

x!=0/3

x!=0

x∈R


We multiply all the terms by the denominator


2x^2-36*3x=0

Wy multiply elements

2x^2-108x=0

a = 2; b = -108; c = 0;
Δ = b2-4ac
Δ = -1082-4·2·0
Δ = 11664
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{11664}=108$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-108)-108}{2*2}=\frac{0}{4}
=0
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-108)+108}{2*2}=\frac{216}{4}
=54
$